AP is a diameter of a unit circle with centre at O. Let AC be an arc of this circle…
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
AP is a diameter of a unit circle with centre at O. Let AC be an arc of this circle, which subtends angle θ radian at centre O. A tangent line is drawn to the circle at the point A and a segement AB on this tangent is laid off whose length is equal to that of the arc AC. A straight line BC is drawn to intersect the extension of the diameter AP at Q. CD is the perpendicular that fall from the point C upon the diameter AP.
The value of the \(\operatorname{Lim}_{\theta \rightarrow 0^{+}} \mathrm{AQ}\) is
- 0
- 1
- 2
- 3
Answer
(D) 3
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