A reaction has ∆H = – 33 kJ and ∆S = +58 J/K. This reaction would be :
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
A reaction has ∆H = – 33 kJ and ∆S = +58 J/K. This reaction would be :
- spontaneous below a certain temperature
- non-spontaneous at all temperature
- spontaneous above a certain temperature
- spontaneous at all temperature
Answer
(D) spontaneous at all temperature
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