The volume of water to be added to N 2 HCl to prepare 500 cm 3 of N 10 solution is:
Chemistry · NEET · NTA Exams — Solutions
The volume of water to be added to \(\frac{\mathrm{N}}{2} \mathrm{HCl}\) to prepare 500 cm3 of \(\frac{N}{10}\) solution is:
- 450 cm3
- 100 cm3
- 45 cm3
- 400 cm3
Answer
(D) 400 cm 3
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