The complete solution set of sin –1 (sin 5) > x 2 – 4x is

Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions

1. \(|x-2|<\sqrt{9-2 \pi}\)
2. \(|x-2|>\sqrt{9-2 \pi}\)
3. \(|x|<\sqrt{9-2 \pi}\)
4. \(|x|>\sqrt{9-2 \pi}\)

Answer

(A) |x-2|< 9-2

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