For |x| 2 + ... to ∞, then dy dx equal to

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

For |x| < 1, let y = 1 + x + x2 + ... to ∞, then \(\frac{\mathrm{dy}}{\mathrm{dx}}\) equal to
  1. \(\frac{x}{y}\)
  2. \(\frac{x^{2}}{y^{2}}\)
  3. \(\frac{\mathrm{x}}{\mathrm{y}^{2}}\)
  4. xy2 + y

Answer

(D) xy 2 + y

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