For |x| 2 + ... to ∞, then dy dx equal to
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
For |x| < 1, let y = 1 + x + x2 + ... to ∞, then \(\frac{\mathrm{dy}}{\mathrm{dx}}\) equal to
- \(\frac{x}{y}\)
- \(\frac{x^{2}}{y^{2}}\)
- \(\frac{\mathrm{x}}{\mathrm{y}^{2}}\)
- xy2 + y
Answer
(D) xy 2 + y
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