Find the value of a for which m = 1 3 is a root of equation. a m^ 2 +( 3 - 2 ) m-1=0
Physics · JEE Main · NTA Exams — Physics and Measurement
Find the value of a for which \(\mathrm{m}=\frac{1}{\sqrt{3}}\) is a root of equation. \(a m^{2}+(\sqrt{3}-\sqrt{2}) m-1=0\)
- \(\sqrt{2}\)
- 2
- \(\sqrt{6}\)
- 5
Answer
(C) 6
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