50 cm 3 of 0.2 N HCI is titrated against 0.1 N NaOH solution. The titration is…
Chemistry · NEET · NTA Exams — Some Basic Concepts of Chemistry
50 cm3 of 0.2 N HCI is titrated against 0.1 N NaOH solution. The titration is discontinued after adding 50 cm3 of NaOH. The remaining titration is completed by adding 0.5 N KOH. The volume of KOH required for completing the titration is:
- 12 cm3
- 10 cm3
- 25 cm3
- 10.5 cm3
Answer
(B) 10 cm 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- 29.5 mg of an organic compound containing nitrogen was digested according to Kjeldahl's method and the…
- When 50 cm 3 of 0.2 N H 2 SO 4 is mixed with 50 cm 3 of 1N KOH, the heat liberated is:
- 4g of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave 5…
- The weights of two elements which combine with one another are in the ratio of their:
- The mass of carbon present in 0.5 mole of K 4 [Fe(CN) 6 ] is:
- Cortisone is a molecular substance containing 21 atoms of carbon per molecule. The weight percentage of…
- A sample of dolomite contained 45% of CaCO 3 , 40% of MgCO 3 and 15% clay. Weight of sulphuric acid of 30%…
- An organic compound is estimated through Dumas method and was found to evolve 6 moles of CO 2 . 4 moles of H…
More Some Basic Concepts of Chemistry questions · Browse all practice questions