The displacement time equation of a particle executing SHM is: x=A (t+ ) . At time t = 0…

Physics · JEE Advanced · NTA Exams — Oscillations and Waves

The displacement time equation of a particle executing SHM is: \(x=A \sin (t+\phi)\). At time t = 0 position of the particle is \(x=\frac{A}{2}\) and it is moving along negative x-direction. Then the angle \(\phi\) can be:
  1. \(\frac{\pi}{6}\)
  2. \(\frac{\pi}{3}\)
  3. \(\frac{2 \pi}{3}\)
  4. \(\frac{5 \pi}{6}\)

Answer

(D) 5 6

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