Let f be a real valued function with domain R satisfying 0 f (x) f (x + a) = 1 2 - f( x…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Let f be a real valued function with domain R satisfying
0 < f (x) < \(\frac{1}{2}\) and for some fixed a,
f (x + a) = \(\frac{1}{2}-\sqrt{f(\mathrm{x})-(f(\mathrm{x}))^{2}} \forall\) x ∈ R
then the peroid of the function f (x) is :
0 < f (x) < \(\frac{1}{2}\) and for some fixed a,
f (x + a) = \(\frac{1}{2}-\sqrt{f(\mathrm{x})-(f(\mathrm{x}))^{2}} \forall\) x ∈ R
then the peroid of the function f (x) is :
- a
- 2a
- non periodic
- none of these
Answer
(B) 2a
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