The emf of cell TI | (0.001 M ) TI ^ + | | (0.0 MM ) ( Cu ^ 2+ . | Cu is 0.83 V at 298 K…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
The emf of cell \(\mathrm{TI}\left|\underset{(0.001 \mathrm{M})}{\mathrm{TI}^{+}}\right|\left|\underset{(0.0 \mathrm{MM})}{\left(\mathrm{Cu}^{2+}\right.}\right| \mathrm{Cu}\) is 0.83 V at 298 K. It could be increased by: (Jee Main 2024)
- decreasing concentration of both Tl+ and Cu2+ ions.
- increasing concentration of Cu2+ ions.
- increasing concentration of Tl+ ions.
- increasing concentration of both Tl+ and Cu2+ ions.
Answer
(B) increasing concentration of Cu 2+ ions.
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