Two blocks, each having a mass M, rest on frictionless surfaces as shown in the figure…
Physics · JEE Main · NTA Exams — Laws of Motion
Two blocks, each having a mass M, rest on frictionless surfaces as shown in the figure. If the pulleys are light and frictionless, and M on the incline is allowed to move down, then the tension in string will be:


- \(\frac{2}{3} M g \sin \theta\)
- \(\frac{3}{2} M g \sin \theta\)
- \(\frac{M g \sin \theta}{2}\)
- 2 Mg sin \(\theta\)
Answer
(C) M g 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A square plate of side 20 cm has uniform thickness and density. A circular part of diameter 8 cm is cut out…
- A particle of mass m moving towards the east with speed v collides with another particle of the same mass and…
- Two blocks of mass 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless…
- A steel ball strikes a steel plate at an angle θ with the vertical. If the coefficient of restitution is e…
- Two ice skaters A and B approach each other at right angles. Skater A has a mass 30 kg and velocity 1 m/s…
- A lift weighing 1000 kg is moving upwards with an acceleration of 1 ~m / s ^ 2 . The tension in the…
- The two pulley arrangements shown in the figure are identical. The mass of the rope is negligible. In (a) the…
- While walking on ice, one should take small steps to avoid slipping. This is because smaller steps ensure
More Laws of Motion questions · Browse all practice questions