When electronic transition occurs from higher energy state to a lower state with energy…

Chemistry · NEET · NTA ExamsStructure of Atom

When electronic transition occurs from higher energy state to a lower state with energy difference equal to ΔE electron volt, the wavelength emitted is approximately equal to:
  1. \(\frac{12431}{\Delta \mathrm{E}} \times 10^{-14} \mathrm{~m}\)
  2. \(\frac{12431}{\Delta \mathrm{E}} \times 10^{14} \mathrm{~m}\)
  3. \(\frac{12431}{\Delta \mathrm{E}} \times 10^{-10} \mathrm{~cm}\)
  4. \(\frac{12431}{\Delta \mathrm{E}} \times 10^{11} \mathrm{~cm}\)

Answer

(C) 12431 E 10^ -10 ~cm

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