The electrostatic potential inside a charged spherical ball is given by =a r^ 2 +b where…

Physics · NEET · NTA ExamsElectrostatics

The electrostatic potential inside a charged spherical ball is given by \(\phi=a r^{2}+b\) where r is the distance from the centre; a, b are constants. Then the charge density inside ball is
  1. \(-6 a E_{a}!\)
  2. \(-24 \pi a \epsilon_{a}!\)
  3. \(-6 \mathrm{aE} \mathrm{E}_{\mathrm{B}}\)
  4. \(-24 a \epsilon_{n}\)

Answer

(C) -6 aE E _ B

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