If a_ 1 , a_ 2 , a_ 3 , , a_ n+1 are in A.P., then 1 a_ 1 a_ 2 + 1 a_ 2 a_ 3 1 a_ n a_…
Mathematics · JEE Main · NTA Exams — Progression and Series
If \(a_{1}, a_{2}, a_{3}, \ldots, a_{n+1}\) are in A.P., then
\(\frac{1}{a_{1} a_{2}}+\frac{1}{a_{2} a_{3}} \ldots \ldots \frac{1}{a_{n} a_{n+1}},\) is
\(\frac{1}{a_{1} a_{2}}+\frac{1}{a_{2} a_{3}} \ldots \ldots \frac{1}{a_{n} a_{n+1}},\) is
- \(\frac{1}{a_{1} a_{n+1}}\)
- \(\frac{\mathrm{n}+1}{\mathrm{a}_{1} \mathrm{a}_{\mathrm{n}+1}}\)
- \(\frac{\mathrm{n}}{\mathrm{a}_{1} \mathrm{a}_{\mathrm{n}+1}}\)
Answer
(D) n a _ 1 a _ n +1
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