The amplitude of sin 5 +i (1- 5 ) is
Mathematics · JEE Main · NTA Exams — Complex Numbers and Quadratic Equations
The amplitude of sin \(\frac{\pi}{5}+i\left(1-\cos \frac{\pi}{5}\right)\) is
- \(\frac{2 \pi}{5}\)
- \(\frac{\pi}{15}\)
- \(\frac{\pi}{10}\)
- \(\frac{\pi}{5}\)
Answer
(C) 10
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