The de-Broglie wavelength associated with a particle of mass m and energy E is h 2 m E …
Physics · NEET · NTA Exams — Physics and Measurement
The de-Broglie wavelength associated with a particle of mass m and energy E is \(\frac{h}{\sqrt{2 m E}}\). Then, the dimensional formula of Planck's constant h is
- \(\mathrm{ML}^{2} \mathrm{~T}\)
- \(\mathrm{ML}^{-1} \mathrm{~T}^{-2}\)
- \(\text { MLT }\)
- \(\mathrm{ML}^{2} \mathrm{~T}^{-1}\)
Answer
(D) ML ^ 2 ~T ^ -1
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