If the circle x^ 2 +y^ 2 +2 x+2 k y+6=0 and x^ 2 +y^ 2 +2 k y+k=0 intersect orthogonally…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
If the circle \(x^{2}+y^{2}+2 x+2 k y+6=0\) and \(x^{2}+y^{2}+2 k y+k=0\) intersect orthogonally, then k is
- \(2 \text { or }-\frac{3}{2}\)
- \(-2 \text { or }-\frac{3}{2}\)
- \(2 \text { or } \frac{3}{2}\)
- \(-2 \text { or } \frac{3}{2}\)
Answer
(B) -2 or - 3 2
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