If the shortest wavelength of transition of H-atom in Lyman series is x, then the correct…

Chemistry · JEE Advanced · NTA Exams — Atomic Structure

1. the longest wavelength in Balmer series of He⁺ is \(\frac{x}{4}\)
2. the shortest wavelength in Balmer series of He⁺ is x
3. the longest wavelength in Lyman series of H atom is \(\frac{4}{3} x\)
4. the longest wavelength in Paschen series of Li²⁺ is \(\frac{16 x}{7}\)

Answer

(B) the shortest wavelength in Balmer series of He + is x, (C) the longest wavelength in Lyman series of H atom is 4 3 x, (D) the longest wavelength in Paschen series of Li 2+ is 16 x 7

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