For a reaction, activation energy E a = 0 and the rate constant at 200 K is 1.6 10^ 5 5^…
Chemistry · NEET · NTA Exams — Chemical Kinetics
For a reaction, activation energy Ea = 0 and the rate constant at 200 K is \(1.6 \times 10^{5} 5^{-1}\). The rate constant at 400 K will be
[Given that gas constant, R = 8.314 J K-1 mol-1]
- \(3.2 \times 10^{6} 5^{-1}\)
- \(3.2 \times 10^{4} 5^{-1}\)
- \(1.6 \times 10^{5} 5^{-1}\)
- \(1.6 \times 10^{3} 5^{-1}\)
Answer
(C) 1.6 10^ 5 5^ -1
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