The solubility product for a salt of the type AB is 4 10^ -1 . What is the molarity of…
Chemistry · NEET · NTA Exams — Equilibrium
The solubility product for a salt of the type AB is \(4 \times 10^{-1}\). What is the molarity of its standard solution?
- \(2 \times 10^{-4} \mathrm{~mol} / \mathrm{L}\)
- \(16 \times 10^{-16} \mathrm{~mol} / \mathrm{L}\)
- \(2 \times 10^{-16} \mathrm{~mol} / \mathrm{L}\)
- \(4 \times 10^{-4} \mathrm{~mol} / \mathrm{L}\)
Answer
(A) 2 10^ -4 ~mol / L
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