For the given reaction, choose the correct expression of K C from the following:- Fe _ (…
Chemistry · JEE Main · NTA Exams — Equilibrium
For the given reaction, choose the correct expression of KC from the following:-
\(\mathrm{Fe}_{(\mathrm{m})}^{3+}+\mathrm{SCN}_{(\mathrm{m})}^{-}\) ⇋ \((\mathrm{FeSCN})_{(\mathrm{mq})}^{2+}\) (Jee Main 2024)
\(\mathrm{Fe}_{(\mathrm{m})}^{3+}+\mathrm{SCN}_{(\mathrm{m})}^{-}\) ⇋ \((\mathrm{FeSCN})_{(\mathrm{mq})}^{2+}\) (Jee Main 2024)
- \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]}{\left[\mathrm{Fe}^{3+}\right][\mathrm{SCN}-]}\)
- \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{Fe}^{3+}\right]\left[\mathrm{SCN}^{-}\right]}{\left[\mathrm{FeSCN}^{2+}\right]}\)
- \(\mathrm{K}_{\mathrm{c}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]}{\left[\mathrm{Fe}^{3+}\right]^{2}\left[\mathrm{SCN}^{-}\right]^{2}}\)
- \(\mathrm{K}_{\mathrm{C}}=\frac{\left[\mathrm{FeSCN}^{2+}\right]^{2}}{\left[\mathrm{Fe}^{3+}\right][\mathrm{SCN}]}\)
Answer
(A) K _ C = [ FeSCN ^ 2+ ] [ Fe ^ 3+ ][ SCN -]
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