Consider the following complex ions, P , Q and R . P = [FeF 6 ] 3 – , Q = [V(H 2 O) 6 ] 2…
Chemistry · JEE Advanced · NTA Exams — Coordination Compounds
Consider the following complex ions, P, Q and R.
P = [FeF6]3–, Q = [V(H2O)6]2+ and R = [Fe(H2O)6]2+.
The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.) is
P = [FeF6]3–, Q = [V(H2O)6]2+ and R = [Fe(H2O)6]2+.
The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.) is
- R < Q < P
- Q < R < P
- R < P < Q
- Q < P < R
Answer
(B) Q R P
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Among the following complexes ( K – P ), K 3 [Fe(CN) 6 ]( K ), [Co(NH 3 ) 6 ]Cl 3 ( L ), Na 3 [Co (oxalate) 3…
- As per IUPAC nomenclature, the name of the complex [Co(H 2 O) 4 (NH 3 ) 2 ] Cl 3 is (2012)
- The IUPAC name of [Ni(NH 3 ) 4 ][NiCl 4 ] is
- Valence bond theory successfully explains the magnetic behaviour of complexes. The substances which contains…
- The spin only magnetic moment value (in Bohr magneton units) of Cr (CO) 6 is (2009)
- The magnetic moment of a complex is 2.83 BM. The complex ion is
- The IUPAC name for [(NH 3 ) 5 Cr – (OH) – Cr(NH 3 ) 5 ] 5+ is
- If the bond length of CO bond in carbon monoxide is 1.128 Å, then what is the value of CO bond length in Fe…
More Coordination Compounds questions · Browse all practice questions