If ω ( ≠ 1) is a cube root of unity, then | array ccc 1 & 1+i+ ^ 2 & ^ 2 1-i & -1 & ^ 2…
Mathematics · JEE Advanced · NTA Exams — Matrices and Determinants
If ω (≠1) is a cube root of unity, then
\[\left|\begin{array}{ccc} 1 & 1+i+\omega^{2} & \omega^{2} \\ 1-i & -1 & \omega^{2}-1 \\ -i & -i+\omega-1 & -1 \end{array}\right|=\]
\[\left|\begin{array}{ccc} 1 & 1+i+\omega^{2} & \omega^{2} \\ 1-i & -1 & \omega^{2}-1 \\ -i & -i+\omega-1 & -1 \end{array}\right|=\]
- 0
- 1
- i
- ω
Answer
(A) 0
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