Two masses m and M are attached with strings as shown. For the system to be in…
Physics · JEE Advanced · NTA Exams — Laws of Motion
Two masses m and M are attached with strings as shown. For the system to be in equilibrium we have:
- \(\tan \theta=1+\frac{2 M}{m}\)
- \(\tan \theta=1+\frac{2 m}{M}\)
- \(\tan \theta=1+\frac{M}{2 m}\)
- \(\tan \theta=1+\frac{m}{2 M}\)
Answer
(A) =1+ 2 M m
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