Given ∆ r S o = –266 and listed [ S _ m ^ o values] calculate S o for Fe 3 O 4 (s) : 4 Fe…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Given ∆rSo = –266 and listed [\(\mathrm{S}_{\mathrm{m}}^{o}\)values] calculate So for Fe3O4(s) :
\(4 \mathrm{Fe}_{3} \mathrm{O}_{4}(\mathrm{~s})[\ldots \ldots .]+\mathrm{O}_{2}(\mathrm{~g})[205] \rightarrow 6 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~S})[87]\)
\(4 \mathrm{Fe}_{3} \mathrm{O}_{4}(\mathrm{~s})[\ldots \ldots .]+\mathrm{O}_{2}(\mathrm{~g})[205] \rightarrow 6 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~S})[87]\)
- +111.1
- +122.4
- +145.75
- 248.25
Answer
(C) +145.75
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