For the reaction, N 2 + 3H 2 → 2NH 3 , if d [ NH _ 3 ] d t =2 10^ -4 ~mol ~L ^ -1 5^ -1 …
Chemistry · NEET · NTA Exams — Chemical Kinetics
For the reaction, N2 + 3H2 → 2NH3, if \(\frac{d\left[\mathrm{NH}_{3}\right]}{d t}=2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} 5^{-1} .\) the value of \(\frac{-\mathrm{d}\left[\mathrm{H}_{2}\right]}{\mathrm{dt}}\) would be:
- \(3 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} 5^{-1}\)
- \(4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} 5^{-1}\)
- \(6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} 5^{-1}\)
- \(1 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} 5^{-1}\)
Answer
(C) 6 10^ -4 ~mol ~L ^ -1 5^ -1
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