The values of a, b and c such that _ x 0 a e^ x -b x+c e^ -x x x =2 are
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
The values of a, b and c such that
\(\lim _{x \rightarrow 0} \frac{a e^{x}-b \cos x+c e^{-x}}{x \sin x}=2\) are
\(\lim _{x \rightarrow 0} \frac{a e^{x}-b \cos x+c e^{-x}}{x \sin x}=2\) are
- a = 1, b = –2, c = 1
- a = 1, b = 2, c = –1
- a = 1, b = 2, c = 1
- a = –1, b = 2, c = 1
Answer
(C) a = 1, b = 2, c = 1
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