Consider the system of equations x – 2 y + 3 z = – 1, – x + y – 2 z = k, x – 3 y + 4 z =…
Mathematics · JEE Advanced · NTA Exams — Matrices and Determinants
Consider the system of equations
x – 2y + 3z = – 1, – x + y – 2z = k, x – 3y + 4z = 1 .
Statement-1 : The system of equations has no solution for k ≠ 3 .
Statement-2 : The determinant
\[\left|\begin{array}{ccc} 1 & 3 & -1 \\ -1 & -2 & k \\ 1 & 4 & 1 \end{array}\right| \neq 0, \text { for } k \neq 3 .\]
x – 2y + 3z = – 1, – x + y – 2z = k, x – 3y + 4z = 1 .
Statement-1 : The system of equations has no solution for k ≠ 3 .
Statement-2 : The determinant
\[\left|\begin{array}{ccc} 1 & 3 & -1 \\ -1 & -2 & k \\ 1 & 4 & 1 \end{array}\right| \neq 0, \text { for } k \neq 3 .\]
- Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation of Statement-1
- Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is False
- Statement-1 is False, Statement-2 is True.
Answer
(C) Statement-1 is True, Statement-2 is False
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