Consider the following cell reaction, 2 Fe ( ~s )+ O _ 2 ( ~g )+4 H ^ + ( aq ) 2 Fe ^ +2…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
Consider the following cell reaction,
\(2 \mathrm{Fe}(\mathrm{~s})+\mathrm{O}_{2}(\mathrm{~g})+4 \mathrm{H}^{+}(\mathrm{aq}) \longrightarrow\) \(2 \mathrm{Fe}^{+2}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(l)\)
\(\mathrm{E}^{\circ}=1.67 \mathrm{~V}\)
At [Fe2+] = 10–3 M, P(O2) = 0.1 atm and pH =3, the cell potential at 25ºC is (2011)
\(2 \mathrm{Fe}(\mathrm{~s})+\mathrm{O}_{2}(\mathrm{~g})+4 \mathrm{H}^{+}(\mathrm{aq}) \longrightarrow\) \(2 \mathrm{Fe}^{+2}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(l)\)
\(\mathrm{E}^{\circ}=1.67 \mathrm{~V}\)
At [Fe2+] = 10–3 M, P(O2) = 0.1 atm and pH =3, the cell potential at 25ºC is (2011)
- 1.47 V
- 1.77 V
- 1.87 V
- 1.57 V
Answer
(D) 1.57 V
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