For a concentrated solution of a weak electrolyte ( K_ q = equilibrium constant) A_ 2 B_…
Chemistry · JEE Main · NTA Exams — Equilibrium
For a concentrated solution of a weak electrolyte (\(K_{\alpha q}=\) equilibrium constant) \(A_{2} B_{3}\) of concentration ‘c’, the degree of dissociation ‘\(\alpha\)’ is
(Jee Main 2023)
(Jee Main 2023)
- \(\left(\frac{K_{a q}}{6 c^{5}}\right)^{\frac{1}{5}}\)
- \(\left(\frac{K_{-s}}{5 c^{4}}\right)^{\frac{1}{5}}\)
- \(\left(\frac{K_{\mathrm{m}}}{25 \mathrm{c}^{2}}\right)^{\frac{1}{5}}\)
- \(\left(\frac{K_{a q}}{108 c^{4}}\right)^{\frac{1}{5}}\)
Answer
(D) ( K_ a q 108 c^ 4 )^ 1 5
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Two solids dissociate as follows A(s) B(g)+C(g) ; K_ p_ 1 =x ~atm ^ 2 (5) [(g)+E(g) ; K_ p_ 2 =y a t m^ 2 …
- G ^ ( HI ; g ) +1.7 ~kJ . What is the equilibrium constant at 25ºC for 2HI(g) ⇌ H 2 (g) + I 2 (g)?
- 3.2 moles of hydrogen iodide were heated in a sealed bulb at 444°C till the equilibrium state was reached…
- 4 moles of A are mixed with 4 moles of B. At equilibrium for the reaction A + B ⇌ C + D, 2 moles of C and D…
- Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R…
- Consider the following equilibrium in a closed container : N 2 O 4 (g) ⇌ 2 NO 2 (g). At a fixed temperature…
- Solubility of MX 2 -type electrolyte is 0.5 × 10 -4 mol/L. Then find out K sp of electrolyte:
- What is the effect of halving the pressure by doubling the volume on the following system at 500°C? H 2 (g) +…