Consider the curve defined implicity by the equation y^ 2 -2 y e^ ^ -1 x +x^ 2 -1+[x]+e^…
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
Consider the curve defined implicity by the equation \(y^{2}-2 y e^{\sin ^{-1} x}+x^{2}-1+[x]+e^{2 \sin ^{-1} x}=0,\) Where
denotes the greatest integer function
The area of the region bounded by the curve between the lines \(x=0\) & \(x=1\) is
- \(\frac{\pi}{2}\)
- \(\frac{\pi}{2}-1\)
- \(\frac{\pi}{2}+1\)
- \(\pi+1\)
Answer
(A) 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If m= _ -2 ^ 0 | x| [ x ]+ 1 2 d x and n= _ 0 ^ 2 | x| [ x ]+ 1 2 d x where represents greatest integer…
- If the line x = α divides the area of region R = ( x , y ) ∈ R 2 : x 3 ≤ y ≤ x , 0 ≤ x ≤ 1 into two equal…
- Consider the curve defined implicity by the equation y^ 2 -2 y e^ ^ -1 x +x^ 2 -1+[x]+e^ 2 ^ -1 x =0, Where…
- If _ x 0 f(x) x^ 2 exists finitely and _ x 0 (1+x+ f(x) x )^ 1 / x =e^ 3 where f ( x ) = a x 2 +b x +c then…
- The area bounded by curve y=e x x and y= x e x is –
- If I_ n = ^ n x d x then I_ n - ( n-1 n ) I_ n-2 =
- Evaluate : 1+x^ 2 n x^ 2 n (1+x^ 2 n )-2 n / n x x^ 2 n+1 d x
- A function which satisfies the relation f(x)=e^ x + _ 0 ^ 1 e^ x f(t) d t then is
More Integral Calculus questions · Browse all practice questions