A compound X decolourises Br 2 water and reacts slowly with conc. H 2 SO 4 to give an…
Chemistry · Class 11 · CBSE — Hydrocarbons
A compound X decolourises Br2 water and reacts slowly with conc. H2SO4 to give an addition product. X reacts with HBr to form Y. Y reacts with NaOH to form Z. On oxidation Z gives hexan-3-one. X, Y and Z in the reactions are 
- X = CH3CH2CH CHCH3, Y = CH3CH2CH(Br)CH(Br)CH2CH3, Z = CH3CH2CH3
- X = CH3CH CHCH3, Y = CH3CH(Br)CH(Br)CH3, Z = CH3CH2CH2OH
- X = CH3CH2CH CHCH2CH3, Y =
, Z = 
- X = CH3CH2CH2CH CHCH3, Y = CH3CH2CH2CH2CH2CH2Br, Z = CH3CH2CH2CH2OH
Answer
(C) X = CH 3 CH 2 CH CHCH 2 CH 3 , Y = , Z =
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