The excess pressure across a soap bubble of radius r is p=[4 T] / r , where T is the…
Physics · NEET · NTA Exams — Properties of Solids and Liquids
The excess pressure across a soap bubble of radius r is \(p=[4 T] / r\), where T is the surface tension of soap solution. Excess pressure across an air bubble of the same radius r formed at a depth h inside a liquid of density ρ is (P0 is atmospheric pressure)
- \(\frac{4 T}{r}+h p g\)
- \(\frac{T}{Z r}\)
- \(\frac{2 T}{r}+h p g+P_{g}\)
- \(\frac{T}{T}\)
Answer
(A) 4 T r +h p g
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