The quantum numbers for the outermost electron of an element are given below n =2, =0, ~m…
Chemistry · JEE Main · NTA Exams — Atomic Structure
The quantum numbers for the outermost electron of an element are given below
\(\mathrm{n}=2, \ell=0, \mathrm{~m}=0, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}\)
The atom is
\(\mathrm{n}=2, \ell=0, \mathrm{~m}=0, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}\)
The atom is
- hydrogen
- lithium
- beryllium
- boron
Answer
(B) lithium
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