A spring of spring constant 5 10^ 3 ~N / m is stretched initially by 5 cm from the…
Physics · NEET · NTA Exams — Work, Energy and Power
A spring of spring constant \(5 \times 10^{3} \mathrm{~N} / \mathrm{m}\) is stretched initially by 5 cm from the unstretched position. The work required to stretch it further by another 5 cm is
- 6.25 N-m
- 12.50 N-m
- 18.75 N-m
- 25.00 N-m
Answer
(C) 18.75 N-m
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