A 5% solution ( w / W ) of cane sugar (molar mass = 342 g mol –1 ) has freezing point 271…
Chemistry · Class 12 · CBSE — Solutions
A 5% solution (w/W) of cane sugar (molar mass = 342 g mol–1) has freezing point 271 K. What will be the freezing point of 5% glucose (molar mass = 18 g mol–1) in water if freezing point of pure water is 273.15 K?
- 273.07 K
- 269.07 K
- 273.15 K
- 260.09 K
Answer
(B) 269.07 K
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