A power radiated by a black body is P 0 and the wavelength corresponding to the maximum…
Physics · JEE Main · NTA Exams — Thermodynamics
A power radiated by a black body is P0 and the wavelength corresponding to the maximum energy is λ0. On changing the temperature of the black body, it was observed that the power radiated is increased to \(\frac{256}{81} \mathrm{P}_{\mathrm{i}}\). The wavelength shift corresponding to the maximum energy will be
- \(+\frac{\lambda_{!}}{4}\)
- \(+\frac{\lambda_{!}}{2}\)
- \(-\frac{\lambda_{B}}{4}\)
- \(-\frac{\lambda_{a}}{2}\)
Answer
(D) - _ a 2
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