_ x 2 x^ 3 -8 x^ 2 -4 is equal to
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\(\lim _{x \rightarrow 2} \frac{x^{3}-8}{x^{2}-4}\) is equal to
- \(\sqrt{6}\)
- \(-\sqrt{6}\)
- \(i \sqrt{6}\)
- none of these
Answer
(B) - 6
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