A sample of CaCO 3 has Ca = 40%, C = 12% and O = 48%. If the law of constant proportions…
Chemistry · JEE Main · NTA Exams — Some Basic Concepts in Chemistry
A sample of CaCO3 has Ca = 40%, C = 12% and O = 48%. If the law of constant proportions is true, then the mass of Ca in 5 g of CaCO3 from another source will be :
- 2.0g
- 0.2g
- 0.02g
- 20.0g
Answer
(A) 2.0g
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