A solution of 1.25g of non-electrolyte in 20g of water freezes at 271.94 K. If K f = 1.86…
Chemistry · JEE Main · NTA Exams — Solutions
A solution of 1.25g of non-electrolyte in 20g of water freezes at 271.94 K. If Kf = 1.86 K Kg mol–1, then the molecular weight of the solute will be \(\left(\mathrm{T}_{\mathrm{f}}^{\circ}=0^{\circ} \mathrm{C}\right)\)
- 179.79g mol–1
- 207.8g mol–1
- 209.6g mol–1
- 109.6g mol–1
Answer
(D) 109.6g mol –1
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