A stone is thrown at an angle θ to the horizontal reaches a maximum height h. The time of…
Physics · JEE Main · NTA Exams — Kinematics
A stone is thrown at an angle θ to the horizontal reaches a maximum height h. The time of flight of the stone is
- \(\sqrt{(2 \mathrm{~h} \sin \theta) / \mathrm{g}}\)
- \(2 \sqrt{(2 h \sin \theta) / g}\)
- \(2 \sqrt{(2 h) / g}\)
- \(\sqrt{(2 \mathrm{~h}) / \mathrm{g}}\)
Answer
(C) 2 (2 h) / g
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