The thermal decomposition of A → B + C has rate constant x mole –1/2 lit 1/2 min –1 at a…
Chemistry · JEE Advanced · NTA Exams — Chemical Kinetics
The thermal decomposition of A \(\text { → }\)B + C has rate constant x mole–1/2 lit1/2 min–1 at a given temperature. How would \(-\frac{\mathrm{A}}{\mathrm{t}}\) will change if concentration of A is doubled keeping temperature constant
- will increase by 2.828 times
- will increase by 4 times
- will increase by 11.313 times
- will not change
Answer
(A) will increase by 2.828 times
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