Two particles of equal mass m go round a circle R under the action of their mutual…
Physics · JEE Main · NTA Exams — Gravitation
Two particles of equal mass m go round a circle R under the action of their mutual gravitational attraction. The speed of each particle is:-
- \(v=\frac{1}{2 R} \sqrt{\frac{1}{G m}}\)
- \(v=\sqrt{\frac{G m}{2 R}}\)
- \(v=\frac{1}{2} \sqrt{\frac{G m}{R}}\)
- \(v=\sqrt{\frac{4 G m}{R}}\)
Answer
(C) v= 1 2 G m R
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