A particle executing SHM while moving from one extremity is found at distances x 1 , x 2…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A particle executing SHM while moving from one extremity is found at distances x1, x2 and x3 from the center at the end of three consecutive seconds, the angular frequency is
- \(\cos ^{-1}\left(\frac{x_{1}+x_{2}}{2 x_{3}}\right)\)
- \(\cos ^{-1}\left(\frac{x_{2}+x_{3}}{2 x_{1}}\right)\)
- \(\cos ^{-1}\left(\frac{x_{1}+x_{3}}{2 x_{2}}\right)\)
- \(\cos ^{-1}\left(\begin{array}{lll} x_{1} & x_{2} & x_{3} \end{array}\right)\)
Answer
(C) ^ -1 ( x_ 1 +x_ 3 2 x_ 2 )
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