In a double slit interference experiment the distance between the slits is 0.05 cm and…

Physics · JEE Main · NTA ExamsOptics

In a double slit interference experiment the distance between the slits is 0.05 cm and screen is 2 m away from the slits. The wavelength of light is 6.0 × 10–5 cm. The distance between the consecutive fringes is
  1. 0.24 cm
  2. 2.21 cm
  3. 1.28 cm
  4. 0.12 cm

Answer

(A) 0.24 cm

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