In a double slit interference experiment the distance between the slits is 0.05 cm and…
Physics · JEE Main · NTA Exams — Optics
In a double slit interference experiment the distance between the slits is 0.05 cm and screen is 2 m away from the slits. The wavelength of light is 6.0 × 10–5 cm. The distance between the consecutive fringes is
- 0.24 cm
- 2.21 cm
- 1.28 cm
- 0.12 cm
Answer
(A) 0.24 cm
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