A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the…

Physics · NEET · NTA ExamsLaws of Motion

A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the force of friction against him is 200 N, then the acceleration of the child is

\(\text { (Take } \left.g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)

  1. \(10 \mathrm{~m} / \mathrm{s}^{2}\)
  2. \(\frac{1}{2} \mathrm{~m} / \mathrm{s}^{2}\)
  3. \(8 \mathrm{~m} / \mathrm{s}^{2}\)
  4. \(2 \mathrm{~m} / \mathrm{s}^{2}\)

Answer

(D) 2 ~m / s ^ 2

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