A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the…
Physics · NEET · NTA Exams — Laws of Motion
A child weighing 25 kg slides down a rope hanging from a branch of a tall tree. If the force of friction against him is 200 N, then the acceleration of the child is
\(\text { (Take } \left.g=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
- \(10 \mathrm{~m} / \mathrm{s}^{2}\)
- \(\frac{1}{2} \mathrm{~m} / \mathrm{s}^{2}\)
- \(8 \mathrm{~m} / \mathrm{s}^{2}\)
- \(2 \mathrm{~m} / \mathrm{s}^{2}\)
Answer
(D) 2 ~m / s ^ 2
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