∆H for the reaction, SO _ 2 ( ~g )+ 1 2 O _ 2 ( ~g ) SO _ 3 ( ~g ) H =-98.3 ~kJ If the…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
∆H for the reaction,
\(\mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_{3}(\mathrm{~g}) \quad \Delta \mathrm{H}=-98.3 \mathrm{~kJ}\)
If the enthalpy of formation of SO3(g) is –395.4 kJ then the enthalpy of formation of SO2(g) is :
\(\mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_{3}(\mathrm{~g}) \quad \Delta \mathrm{H}=-98.3 \mathrm{~kJ}\)
If the enthalpy of formation of SO3(g) is –395.4 kJ then the enthalpy of formation of SO2(g) is :
- –297.1 kJ
- 493.7 kJ
- –493.7 kJ
- 297.1 kJ
Answer
(A) –297.1 kJ
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