A table tennis ball has radius (3/2) × 10 −2 m and mass (22/7) × 10 −3 kg. It is slowly…

Mathematics · JEE Advanced · NTA ExamsTrigonometry

A table tennis ball has radius (3/2) × 10−2 m and mass (22/7) × 10−3 kg. It is slowly pushed down into a swimming pool to a depth of d = 0.7 m below the water surface and then released from rest. It emerges from the water surface at speed v, without getting wet, and rises up to a height H. Which of the following option(s) is(are) correct?
[Given: π = 22/7, g = 10 m s−2,
density of water = 1 × 103 kg m−3,
viscosity of water = 1 × 10−3 Pa-s.]
  1. The work done in pushing the ball to the depth d is 0.077 J.
  2. If we neglect the viscous force in water, then the speed v = 7 m/s.
  3. If we neglect the viscous force in water, then the height H = 1.4 m.
  4. The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is 500/9 .

Answer

(D) The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is 500/9 .

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