The value of _ -2 ^ 3 |1-x^ 2 | d x is,
Mathematics · JEE Main · NTA Exams — Integral Calculus
The value of \(\int_{-2}^{3}\left|1-x^{2}\right| d x\) is,
- \(\frac{28}{3}\)
- \(\frac{14}{3}\)
- \(\frac{7}{3}\)
- \(\frac{1}{3}\)
Answer
(A) 28 3
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