If the circle x 2 + y 2 + 2x + 2ky + 6 = 0 and x 2 + y 2 + 2ky + k = 0 intersect…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
If the circle x2 + y2 + 2x + 2ky + 6 = 0 and
x2 + y2 + 2ky + k = 0 intersect orthogonally, then k is :
x2 + y2 + 2ky + k = 0 intersect orthogonally, then k is :
- 2 or –3/2
- –2 or –3/2
- 2 or 3/2
- –2 or 3/2
Answer
(A) 2 or –3/2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The distance between the lines represented by the equation, x^ 2 +2 2 y+2 y^ 2 +4 x+4 2 y+1=0 is :
- Let 3 denote the three-dimensional space. Take two points P = (1, 2, 3) and Q = (4, 2, 7). Let dist ( X , Y )…
- ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6. If A…
- A variable circle having fixed radius ‘a’ passes through origin and meets the coordinate axes in point A and…
- The equation of the circle which is touched by y = x, has its centre on the positive x-axis & cuts off a…
- If α 1 , α 2 , α 3 , β 1 , β 2 , β 3 are the values of n for which _ r=0 ^ n-1 x^ 2 r is divisible by then…
- If α + β = 3π then the chord joining the points α and β for the hyperbola x^ 2 a^ 2 - y^ 2 b^ 2 =1 passes…
- The set of values of ‘b’ for which the origin and the point (1, 1) lie on the same side of the straight line…
More Co-ordinate Geometry questions · Browse all practice questions